Question

The number of turns in a secondary coil is twice the number of turns in primary. A leclanche cell of 1.5V is connected across the primary. The voltage across secondary is :_______

Answer 1

Using the transformer equation, which relates the ratio of secondary to primary voltages with the turns ratio, and knowing the primary voltage is 1.5V and the secondary has twice as many turns, we calculate the secondary voltage to be 3 volts.

Step-by-step explanation:

The student's question pertains to the working of a transformer and specifically how to calculate the voltage across the secondary coil given the voltage across the primary coil and the ratio of the number of turns in the coils. The transformer equation is used to solve this problem. It states that the ratio of the secondary voltage (Vs) to the primary voltage (Vp) in a transformer equals the ratio of the number of turns in the secondary coil (Ns) to the number of turns in the primary coil (Np).

In this case, the number of turns in the secondary coil is twice that of the primary, so Ns/Np = 2/1. Given that the primary voltage is 1.5 V, we can set up the equation Vs/Vp = Ns/Np which gives us Vs/1.5V = 2/1. Solving this, we find that Vs = 3V. So, the voltage across the secondary is 3 volts.