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Write the equation of the line that is perpendicular to x + y = -5 and passes through the point (7,3).

Write the equation of the line that is perpendicular to 5x + 3y = -21 and passes through the point (-5, 1).

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Final answer:

To find the equation of a line that is perpendicular to a given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope.

Step-by-step explanation:

To find the equation of a line that is perpendicular to a given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope. First, let's find the slope of the given line x + y = -5 by putting it in slope-intercept form (y = mx + b).

Subtract x from both sides: y = -x - 5. Now we can see that the slope of this line is -1.

The negative reciprocal of -1 is 1. So, the slope of the line perpendicular to x + y = -5 is 1. Using the point-slope form (y - y1 = m(x - x1)), we can now write the equation of the line that passes through the point (7, 3):

y - 3 = 1(x - 7)

y - 3 = x - 7

y = x - 4

Therefore, the equation of the line that is perpendicular to x + y = -5 and passes through the point (7, 3) is y = x - 4.

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