216k views
1 vote
Write the equation of the line that is perpendicular to x + y = -5 and passes through the point (7,3).

Write the equation of the line that is perpendicular to 5x + 3y = -21 and passes through the point (-5, 1).

1 Answer

2 votes

Final answer:

To find the equation of a line that is perpendicular to a given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope.

Step-by-step explanation:

To find the equation of a line that is perpendicular to a given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope. First, let's find the slope of the given line x + y = -5 by putting it in slope-intercept form (y = mx + b).

Subtract x from both sides: y = -x - 5. Now we can see that the slope of this line is -1.

The negative reciprocal of -1 is 1. So, the slope of the line perpendicular to x + y = -5 is 1. Using the point-slope form (y - y1 = m(x - x1)), we can now write the equation of the line that passes through the point (7, 3):

y - 3 = 1(x - 7)

y - 3 = x - 7

y = x - 4

Therefore, the equation of the line that is perpendicular to x + y = -5 and passes through the point (7, 3) is y = x - 4.

User Damn Vegetables
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories