175k views
1 vote
What is the end behavior of function h?

h(x)= -4x^2+ 11
As x approaches negative infinity, h(x) approaches ____________
As x approaches positive infinity,

User Wenger
by
7.9k points

1 Answer

5 votes

Final answer:

The end behavior of function h(x) = -4x^2 + 11 is as x approaches negative infinity, h(x) approaches positive infinity, and as x approaches positive infinity, h(x) approaches negative infinity.

Step-by-step explanation:

The end behavior of a function describes what happens to the values of the function as x approaches positive or negative infinity. For the function h(x) = -4x^2 + 11, as x approaches negative infinity, the function approaches positive infinity. This is because as x becomes more and more negative, the negative term -4x^2 becomes larger and larger, resulting in a function value that approaches positive infinity. As x approaches positive infinity, the function h(x) approaches negative infinity. This is because as x becomes more and more positive, the term -4x^2 becomes larger and larger, resulting in a function value that approaches negative infinity.

User Rgrinberg
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.