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A cannon ball is launched off a 100 m cliff horizontally with an initial Horizontal velocity of 50 m/s. How far will it travel,(what is the range)?"

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Final answer:

The cannonball will not travel any horizontal distance and will fall straight down from the cliff.

Step-by-step explanation:

To calculate the range of a projectile, we can use the formula:

R = (v^2 * sin(2θ))/g

Where:

  • R is the range
  • v is the initial horizontal velocity (given as 50 m/s)
  • θ is the launch angle (in this case, 0° because it is launched horizontally)
  • g is the acceleration due to gravity (9.8 m/s^2)

Plugging in the values, we get:

R = (50^2 * sin(0))/9.8 = 0 m

Therefore, the cannonball will not travel any horizontal distance and will fall straight down from the cliff.

User Saeid Doroudi
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