Question

A=x^2=4 and x∈Z
B={-2,-1,0,1}
A∪B =
A∩B =
A\B =
B\A=

Answer 1

Set A is defined by integers satisfying the equation x^2 = 4, which are -2 and 2. Therefore, A union B is {-2, -1, 0, 1, 2}, A intersection B is {-2}, A minus B is {2}, and B minus A is {-1, 0, 1}.

Step-by-step explanation:

The student has provided definitions for two sets A and B, and we need to find A ∪ B (A union B), A ∩ B (A intersection B), A \ B (A minus B), and B \ A (B minus A). First, let's determine set A by finding the integers (x) that satisfy the equation x2 = 4. We find that A = {-2, 2}. Now we can find:

• A ∪ B as the set containing all unique elements from both A and B, which is {-2, -1, 0, 1, 2}.
• A ∩ B as the set containing only the elements that are in both A and B, which is {-2}.
• A \ B as the set containing elements in A that are not in B, which is {2}.
• B \ A as the set containing elements in B that are not in A, which is {-1, 0, 1}.