Final answer:
The minimum distance from point P(2, 2) to the line 3x+4y+1=0 is 3 units.
Step-by-step explanation:
To find the minimum distance from point P(2, 2) to the line 3x+4y+1=0, we can use the formula for the distance between a point and a line:
d = |ax + by + c| / sqrt(a^2 + b^2)
Plugging in the values from the given equation, we have:
d = |3(2) + 4(2) + 1| / sqrt(3^2 + 4^2)
d = |6 + 8 + 1| / sqrt(9 + 16)
d = |15| / sqrt(25)
d = 15 / 5
d = 3
So, the minimum distance from point P(2, 2) to the line 3x+4y+1=0 is 3 units.