Question

Hurry, I need a quick answer right away? Find the X!!!! Radical answer!!!

Answer 1

Given to find the side of right angle triangle.

use the formula,

`\sin \theta=\frac{opposite\text{ }}{\text{hypotenouse}}`
`\begin{gathered} \sin 30^(\circ)=\frac{\sqrt[]{2}}{y} \\ (1)/(2)=\frac{\sqrt[]{2}}{y} \\ y=2\sqrt[]{2} \end{gathered}`
`\begin{gathered} \sin 60^(\circ)=\frac{x}{2\sqrt[]{2}} \\ \frac{\sqrt[]{3}}{2}=\frac{x}{2\sqrt[]{2}} \\ 2x=2\sqrt[]{2}\cdot\sqrt[]{3} \\ x=\sqrt[]{6} \end{gathered}`
`\begin{gathered} \tan 60=\frac{x}{\sqrt[]{2}} \\ \sqrt[]{3}=\frac{x}{\sqrt[]{2}} \\ x=\sqrt[]{6} \end{gathered}`

so the answer is,

`x=\sqrt[]{6}`