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What is the equation in point slope form for the line

parallel to y=5x-4 that contains PC-6,1)?
y-5=6(x+1)
y+6=5(x-1)
y-1=5(X+6)

User Jeison
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1 Answer

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Final answer:

The equation in point slope form for the line parallel to y = 5x - 4 that contains the point (-6, 1) is y - 1 = 5(x + 6).

Step-by-step explanation:

To find the equation in point slope form for a line parallel to y = 5x - 4 that contains the point (-6, 1), we need to use the same slope as the given line, which is 5. The point slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. Plugging in the values, we get y - 1 = 5(x - (-6)). Simplifying further, we have y - 1 = 5(x + 6).

User Joshpt
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