Final answer:
Approximately 24.84 grams of water will absorb 1559 Joules of energy for the temperature change from 30°C to 45°C using the formula q=mcΔT and the specific heat capacity of water, which is 4.184 J/(g°C).
Step-by-step explanation:
To find out what mass of water will absorb 1559 Joules of energy when it goes from 30°C to 45°C, we use the formula for heat transfer q=mcΔT, where q is the heat energy absorbed or released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. We know the specific heat capacity of water, which is 4.184 J/(g°C), the heat energy q is given as 1559 Joules, and the temperature change ΔT is (45°C - 30°C), which is 15°C.
Plugging in the known values we have:
1559 J = m (4.184 J/g°C) (15°C)
Therefore:
m = 1559 J / (4.184 J/g°C × 15°C)
m = 1559 / 62.76
m ≈ 24.84 g
So a mass of approximately 24.84 grams of water will absorb 1559 Joules of energy for the temperature change from 30°C to 45°C.