Final answer:
To find the compound with the lowest percent gold content, we calculate the mass percentage of gold in each compound. For AuOH, this involves dividing the atomic mass of gold by the sum of the atomic masses of all elements in the molecule. Without exact figures, we can only describe the methodology for comparison.
Step-by-step explanation:
To determine which compound has the lowest percent gold content by weight out of the options provided, we must first look at the molecular formula of gold hydroxide: AuOH. Then, we'll calculate the molar mass of AuOH, which includes the atomic mass of gold (Au), oxygen (O), and hydrogen (H). By comparing this with the other compounds such as Gold(V) Fluoride (AuF5), we can establish which has the lowest gold percentage by mass.
To calculate the percent gold content in AuOH, the mass of gold within the molecule is divided by the molar mass of the entire compound, then multiplied by 100. As we do not have the exact atomic masses given, we would generally use the standard atomic weights: Au (197.0 g/mol), O (16.0 g/mol), and H (1.00 g/mol). Thus, the molar mass of AuOH is approximately the sum of these values. Afterward, the mass percentage of gold in AuOH can be expressed as (197.0 g/mol) / (197.0 g/mol + 16.0 g/mol + 1.00 g/mol) * 100%, which would yield the percent gold content.
As for the other compounds like Gold(V) Fluoride (AuF5), we would perform a similar calculation to find the percent gold content. Since the question specifies only one answer, and we do not have the actual atomic masses for a precise calculation, we can only outline the comparison method rather than providing specific percentages. The compound with more mass of other elements relative to gold will have a lower percent gold content.