127k views
5 votes
The equation of the circle with center (3,0) containing the point (-2, √56)

User Lknls
by
8.0k points

1 Answer

0 votes

Final answer:

The equation of the circle with center (3,0) containing the point (-2, √56) is (x - 3)^2 + y^2 = 9.

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is given by the equation:

(x - h)^2 + (y - k)^2 = r^2

In this case, the center of the circle is (3, 0) and the circle contains the point (-2, √56).

To find the radius of the circle, we need to calculate the distance between the center and the given point:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Substituting the values into the formula:

Distance = √((-2 - 3)^2 + (√56 - 0)^2)

Distance = √(25 + 56)

Distance = √81 = 9

Therefore, the equation of the circle is: (x - 3)^2 + y^2 = 9

User Kev Riley
by
7.3k points