Final answer:
The inequality for the possible number of games played within a $10.00 budget, after a $3.00 admission fee, is 3.00 + 0.25g ≤ 10.00. Solving for g, we find the maximum number of games that can be played is 28.
Step-by-step explanation:
To represent the possible number of games that can be played at the fall carnival within a $10.00 budget, we need to create an inequality. First, we subtract the admission fee from the total amount of money available.
Let g = the number of games played. The cost for each game is $0.25, and the admission fee is $3.00. The inequality that represents this situation is:
3.00 + 0.25g ≤ 10.00
To find the maximum number of games that can be played, solve the inequality for g:
0.25g ≤ 10.00 - 3.00
0.25g ≤ 7.00
g ≤ 7.00 / 0.25
g ≤ 28
Therefore, the maximum number of games that can be played is 28.