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A jogger jogs 25 meters South to the east and then 25 meters west back home. For this motion, what is the distance moved?"

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Final answer:

The distance moved by a jogger involves adding the magnitudes of each leg of the jog. Displacement would be the straight-line distance from the start to endpoint, but the distance covered includes all the paths taken, regardless of their direction.

Step-by-step explanation:

The question is asking to calculate the total distance a jogger has traveled. It appears there is an error in the initial question's description of the jogger's path, but based on the context provided, we can tackle similar problems using vector addition. When considering a walk or jog as a series of vector displacements, you add the vectors to find the resultant displacement and calculate the total distance traveled by summing the magnitudes of each individual journey segment.

For instance, if someone walks first 25.0 m northeast, then 23.0 m north of east, and finally 32.0 m south of east, these three vectors would be added graphically or analytically to determine the total displacement. If the person's path involved straight-line walks south and back north or east and west, the resultant displacement might be straight-line distance back to their starting point, but the distance walked would still be the sum of the individual distances walked in each leg.

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