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Find the equation of a square root function with a starting point of (-1,6) and passing through (3, 16)."

User Delux
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Final answer:

To find the square root function, the general form f(x) = a√(x - h) + k is used with the starting point (-1, 6) leading to f(x) = a√(x + 1) + 6. Using another point (3, 16), the parameter 'a' is found to be 5, giving the equation of the function as f(x) = 5√(x + 1) + 6.

Step-by-step explanation:

To find the equation of a square root function that starts at (-1, 6) and passes through (3, 16), we need to establish a general form of the function and then use the given points to find the specific parameters.

A square root function generally has the form:

f(x) = a√(x - h) + k

Where (h, k) is the starting point, and 'a' is a scaling factor.

Using the starting point (-1, 6), our function takes the form:

f(x) = a√(x + 1) + 6

Now, using the point (3, 16) to solve for 'a':

f(3) = a√(3 + 1) + 6 = 16

a√4 + 6 = 16

2a + 6 = 16

2a = 10

a = 5

Therefore, the equation of the square root function is:

f(x) = 5√(x + 1) + 6

User Mani Jagadeesan
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