Question

A homing pigeon was released from its cage at 10:00 am. At that time, the cage was 108.0 m from the pigeon’s home. If the pigeon returns to its home at 10:04 am, what was the pigeon’s average velocity?

Answer 1

The average velocity of the homing pigeon is -0.45 m/s, indicating that the pigeon is moving in the opposite direction of its home.

Step-by-step explanation:

The average velocity of the homing pigeon can be calculated by dividing the total displacement by the total time taken. In this case, the pigeon's initial position is 108.0 m from its home, and it returns to its home 4 minutes later, which is equal to 240 seconds. The displacement is the difference between the final position (0 m) and the initial position (-108.0 m), which is -108.0 m. Therefore, the average velocity is:

Average velocity = displacement / time = -108.0 m / 240 s = -0.45 m/s

Since velocity is a vector quantity, the negative sign indicates that the pigeon is moving in the opposite direction of its home.