Question

A baseball has a velocity of 65 m/s downward after 8.5 seconds in free fall. An object in freefall will

accelerate at 10 m/s/s, downward, What was the baseball's original velocity?

Answer 1

The original velocity of the baseball was 20 m/s upward, derived using the equation of motion v = u + at, where the final velocity v is -65 m/s, acceleration a is -10 m/s^2, and time t is 8.5 seconds.

Step-by-step explanation:

The student has asked about the original velocity of a baseball that has a velocity of 65 m/s downward after 8.5 seconds in freefall, considering the acceleration due to gravity is 10 m/s2 downward.

We can use the equation of motion for velocity in freefall, which is v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. In this scenario, we know that:
v = -65 m/s (downward, hence negative),
a = -10 m/s2 (downward, hence negative),
t = 8.5 s.

Substituting the known values into the equation, we get:
-65 m/s = u - (10 m/s2)(8.5 s).
Solving for u, we find:
u = -65 m/s + (10 m/s2)(8.5 s).
u = -65 m/s + 85 m/s.
u = 20 m/s.

Therefore, the original velocity of the baseball was 20 m/s upward.