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A woman driving a car traveling at 40 m/a slams on the brakes and deaccelerates at 4 m/s^2. How far does the car travel before it stops?

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Final answer:

To calculate the stopping distance of a car decelerating at 4 m/s^2 from 40 m/s, the equation v^2 = u^2 + 2as is used, resulting in a stopping distance of 200 meters.

Step-by-step explanation:

A woman driving a car traveling at 40 m/s slams on the brakes and decelerates at 4 m/s2. To calculate how far the car will travel before it stops, we can use the formula for displacement under constant acceleration, which is:

v2 = u2 + 2as,

where v is the final velocity, u is the initial velocity, a is the acceleration (deceleration in this case since it will be negative), and s is the displacement.

Since the car comes to a stop, v = 0 m/s, so the formula becomes:

0 = (40 m/s)2 + 2(-4 m/s2)s,

0 = 1600 m2/s2 - 8s,

s = 1600/8 = 200 meters.

Therefore, the car travels 200 meters before it comes to a stop.

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