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Which of the following equations are quadratic equations? Explain how you know

y = -2(x - 3)2 – 5,
f(3) = V2+4 - 4,
7x2 + 3y = 12
202 + 3y2 = 12

1 Answer

4 votes

Final answer:

The equation y = -2(x - 3)^2 – 5 is a quadratic equation because it has a squared term. The equation 7x^2 + 3y = 12 is quadratic in x due to the x^2 term. The equation 20x^2 + 3y^2 = 12, while not a standard one-variable quadratic equation, also falls under the family of quadratics since both x and y are squared.

Step-by-step explanation:

The equations to be analyzed for their quadratic nature are y = -2(x - 3)^2 – 5, 7x^2 + 3y = 12, and 20x^2 + 3y^2 = 12. A quadratic equation is an equation of the second degree, which means it includes at least one term that is squared. The standard form of a quadratic equation in one variable is ax^2 + bx + c = 0, where a, b, and c are constants, and a is not equal to 0.

The first equation, y = -2(x - 3)^2 – 5, is a quadratic equation because it has the term (x - 3)^2, which is the square of a binomial, indicating that x is raised to the second power.

The second equation, 7x^2 + 3y = 12, is a quadratic equation in x because it includes the x^2 term.

The third equation, 20x^2 + 3y^2 = 12, is not a standard quadratic equation in one variable, but it is a quadratic in two variables because both x and y are squared. It is therefore part of the family of quadratic equations, but not a pure quadratic equation in the sense of having a single variable squared.

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