Question

I'm not sure what to do after this, but can you please answer the problem with the method I used I get confused with using other methods.

Answer 1

we have the expression

`(3y+2)/(3y)\colon(6y^2+4y)/(3y+2)`

step 1

Simplify the second term

so

`\begin{gathered} (3y+2)/(3y)\colon(2y(3y+2))/(3y+2) \\ \\ (3y+2)/(3y)\colon2y \end{gathered}`

step 2

Multiply in cross

`((3y+2))/(3y\cdot2y)`
`((3y+2))/(6y^2)=(1)/(2y)+(1)/(3y^2)`