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1)A 2.0 kilogram wooden object is a on a wooden surface. What is the maximum force of friction that can be produced in this system?

1 Answer

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Answer:

fr = 7.84 N

Step-by-step explanation:

To solve this exercise we must use Newton's second law, the case of translational equilibrium

F -fr = 0

F = fr

where F is the applied force and fr the friction force

for the Y axis

N -W =

N = W

N = m g

the friction force has the equation

fr = μ N

fr = μ m g

in this case they indicate the two materials that are in contact with wood on wood, so when reviewing the tables the coefficient of static friction is μ=0.4

let's calculate

fr = 0.4 2.0 9.8

fr = 7.84 N

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