Final answer:
To make a saturated solution at 60°C in 280 g of solvent with a solubility of 70 g per 100 g of solvent, one would need 196 g of the solute.
Step-by-step explanation:
To determine how much solute is required to make a saturated solution in 280 grams of solvent at 60°C, we can use the provided solubility data. The solubility of the salt is given as if it were 70°C, but assuming that this is a typographical error and the solubility is indeed for 60°C, we can proceed. If the solubility is 70 g per 100 g of solvent, then for 280 g of solvent, the calculation is as follows:
(70 g solute / 100 g solvent) × 280 g solvent = 196 g of solute.
This means you would need 196 grams of the solute to make a saturated solution in 280 grams of solvent at 60°C.