Question

A truck moving at an initial velocity of30 m/s is brought to astop in 10 s. What was the acceleration of the car, and what was the stoppingdistance?

Answer 1

The acceleration of the truck is -3 m/s². The stopping distance can be calculated using the initial velocity, time, and calculated acceleration.

Step-by-step explanation:

The student question pertains to calculating the acceleration of a truck that is brought to a stop and determining the stopping distance given an initial velocity and the time taken to stop. To find the acceleration, one can use the formula a = (v_f - v_i) / t, where v_f is the final velocity (0 m/s since the truck stops), v_i is the initial velocity (30 m/s), and t is the time (10 s). The stopping distance can then be calculated using the formula d = v_i * t + 0.5 * a * t^2.

When calculated, the acceleration (a) of the truck is -3 m/s² since the truck is decelerating. The stopping distance (d) can be found by substituting the initial velocity, time, and calculated acceleration into the second formula.