Question

A 90 g of a mysterious substance was heated from 23.0°C to 85.0°C using 127 J of heat. To identify the substance we need to know the specific heat capacity of it. What is the mysterious substance's specific heat capacity?

Answer 1

The specific heat capacity of the substance is calculated using the formula q = mcΔT and is found to be approximately 0.023 J/g°C. Without a reference table, we cannot identify the substance.

Step-by-step explanation:

The specific heat capacity of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius. To calculate the specific heat capacity, we use the formula q = mcΔT, where q is the heat added in joules, m is the mass in grams, and ΔT is the change in temperature in degrees Celsius.

In the given problem, we have:

• Mass (m) = 90 g
• Heat energy (q) = 127 J
• Initial temperature = 23.0°C
• Final temperature = 85.0°C
  Thus, Δ

(change in temperature) = 85.0°C - 23.0°C = 62.0°C.

Now we can rearrange the formula to solve for the specific heat capacity (c): c = q / (mΔT). Plugging in the values gives us: c = 127 J / (90 g × 62.0°C). After calculating, we find that the specific heat capacity of the substance is approximately 0.023 J/g°C.

Without knowing what substances are listed in Table 9.1 or Table 5.1, we cannot conclusively identify the substance. If a list were provided, we would look for a substance with a specific heat capacity close to the calculated value to determine the likely identity of the mysterious substance.