Final answer:
The change in length of the lead sample is approximately 6.669m.
Step-by-step explanation:
To determine the change in length of the lead sample, we can use the formula:
ΔL = αLΔT
Where ΔL is the change in length, α is the linear coefficient of thermal expansion, L is the original length, and ΔT is the change in temperature.
For lead, the linear coefficient of thermal expansion is approximately 0.0000291 per degree Celsius.
Given that the original length is 659m, the change in temperature is 342°C (367°C - 25°C), and α is 0.0000291, we can calculate the change in length as follows:
ΔL = (0.0000291)(659)(342)
ΔL ≈ 6.669m
Therefore, the change in length of the lead sample is approximately 6.669m.