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Evaluate using synthetic division: f(x) = x3 +6x2 + 12x + 25 given the
value of x = -4

User Shea Levy
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1 Answer

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Final answer:

To evaluate the function f(x) = x^3 + 6x^2 + 12x + 25 using synthetic division, divide the coefficients of the function by the given value of x = -4.

Step-by-step explanation:

To evaluate the function f(x) using synthetic division, we will divide the coefficients of the function by the given value of x = -4.

First, let's set up the synthetic division table:

-4 | 1 6 12 25
|

Starting with the coefficient 1, we bring it down to the line:

-4 | 1 6 12 25
| 1

Next, we multiply the divisor -4 by the 1 and write the result below the next coefficient:

-4 | 1 6 12 25
| 1
|-4

Adding the two values, we get 2, which becomes the next coefficient:

-4 | 1 6 12 25
| 1 -4
|-4
----
1 2

Continuing this process, we repeat the steps until all coefficients have been evaluated:

-4 | 1 6 12 25
| 1 -4 -4
|-4 12
----
1 2 8

The last value, 8, is the remainder. The values in the bottom row represent the coefficients of the quotient polynomial. Therefore, the quotient polynomial is: x^2 + 2x + 8.

User DmitMedv
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