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ATOMIC MATH

Solve the problem as we did in class, starting each step with the answer from the previous step.
NO DECIMALS; NO NEGATIVE NUMBERS.
Add the atomic number of radium, Ra, to the number of electrons in argon, Ar:
Subtract the atomic mass (rounded) of sodium, Na:
Multiply by the number of protons in beryllium, Be:
Divide by the number of electrons in helium, He:
Subtract the number of neutrons in iron, Fe:

1 Answer

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Final answer:

To solve the atomic math problem, one must perform a sequence of arithmetic operations involving atomic numbers and mass numbers of various elements, leading to a final answer of 136.

Step-by-step explanation:

To solve this atomic math problem, we need to follow the instructions step by step. We'll utilize the periodic table and general atomic knowledge to calculate our answer.

  1. Add the atomic number of radium (88) to the number of electrons in argon (18): 88 + 18 = 106.
  2. Subtract the atomic mass (rounded) of sodium (23) from the result: 106 - 23 = 83.
  3. Multiply by the number of protons in beryllium (4): 83 x 4 = 332.
  4. Divide by the number of electrons in helium (2): 332 / 2 = 166.
  5. Subtract the number of neutrons in iron (30, from an iron-56 atom which has 26 protons and hence 56 - 26 = 30 neutrons): 166 - 30 = 136.

The final answer to the problem is 136.

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