Final answer:
To raise the temperature of 30 grams of water from 0°C to 100°C, 12,552 joules of energy is required, based on the specific heat capacity of water (4.184 J/g°C), using the formula Q = mcΔT.
Step-by-step explanation:
To calculate the heat required to raise the temperature of 30 grams of water from 0°C to 100°C, we use the specific heat capacity of water and the formula Q = mcΔT. The specific heat capacity of water is 4.184 J/g°C. This is the amount of energy needed to raise the temperature of 1 gram of water by 1°C. Given that we have 30 grams of water and a temperature change (ΔT) of 100°C (from 0°C to 100°C), the energy required (Q) can be calculated as follows:
Q = mcΔT
Q = (30 g) * (4.184 J/g°C) * (100°C)
Q = 12552 J
Therefore, 12,552 joules of energy is required to heat 30 grams of water from 0°C to 100°C.