Final answer:
Abby is incorrect in her calculation. The correct percentage of schnauzers at the dog show is about 42.86%, not 75%, as she mistakenly divided the number of schnauzers by the number of poodles instead of the total number of dogs.
Step-by-step explanation:
Abby calculated that 3/4 or 75% of the dogs at the Manhattan Dog Show are schnauzers based on seeing 3 schnauzers and 4 poodles. To determine whether Abby is correct, we need to find the fraction of schnauzers out of the total number of dogs.
To calculate the percentage of schnauzers, we take the number of schnauzers (3) and divide by the total number of dogs. The total number of dogs is the sum of schnauzers and poodles together, which is 3 (schnauzers) + 4 (poodles) = 7 dogs.
So, the calculation is 3 schnauzers ÷ 7 total dogs, which gives us 3/7. To convert this fraction to a percentage, we multiply by 100, resulting in approximately 42.86%.
Thus, Abby's calculation of 75% is incorrect as the actual percentage of schnauzers is roughly 42.86%. Abby made the error of using the number of poodles as the denominator instead of the total number of dogs to calculate the percentage.