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What is the equation of the parabola that has a y-intercept of 12, an a-value of -2, and passes through the point (-10, 7)?"

User Eryka
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1 Answer

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Final answer:

The equation of the parabola is y = 0.07x².

Step-by-step explanation:

The equation of a parabola can be written in the form y = ax + bx², where a and b are constants. To find the equation of the parabola, we need to determine the values of a and b.

Given that the y-intercept is 12, we can substitute the point (0,12) into the equation to get 12 = a(0) + b(0)². This simplifies to 12 = 0, so we know that a is 0.

Next, we can substitute the point (-10,7) into the equation to get 7 = a(-10) + b(-10)². Since we know that a is 0, this further simplifies to 7 = 0 + 100b. Solving for b, we find that b is 0.07.

Therefore, the equation of the parabola is y = 0 + 0.07x², which simplifies to y = 0.07x².

User Brett Lempereur
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