Question

Marianne had 128 brood cows. She lost 2 cows and calves during calving and 3 calves were born dead. She had 4 cows that did not calve.a. What percent of the cows was lost? Express your answer to the nearest tenth of a percent.b. How many calves does she have?c. What percent of the cows have a calf at their side? Express your answer to the nearest tenth of a percent.

Answer 1

Marianne had 128 brood cows. She lost 2 cows and calves during calving and 3 calves were born dead. She had 4 cows that did not calve.



a. What percent of the cows was lost? Express your answer to the nearest tenth of a percent.



b. How many calves does she have?



c. What percent of the cows have a calf at their side? Express your answer to the nearest tenth of a percent.

Part a

total original cows=128 ------> represent 100%

so

Applying proportion

Find out how much percentage represent 2 cows

100/128=x/2

solve for x

x=(100/128)*2

x=1.6%

Part b

total cows=128-2=126

total calves=126-3-4=119 calves

Part c

total cows=126

total cows that have a calf at their side=119

applying proportion

100/126=x/119

solve for x

x=(100/126)*119

x=94.4%