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Use LONG DIVISION to divide 3x^3 - 7x^2 + 5x^2 - 3 by 2x^2 + 3. Is the divisor a factor?

A) Yes, it's a factor.
B) No, it's not a factor.
C) Partially a factor.
D) Cannot be determined.

User Too
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1 Answer

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Final answer:

By performing long division, we find that 2x^2 + 3 is not a factor of 3x^3 - 7x^2 + 5x^2 - 3 as there is a non-zero remainder. The answer is B) No, it's not a factor.

Step-by-step explanation:

To determine if 2x^2 + 3 is a factor of 3x^3 - 7x^2 + 5x^2 - 3, we need to use long division. Before we start, let's simplify the polynomial by combining like terms, in this case, the x^2 terms. So, the polynomial simplifies to 3x^3 - 2x^2 - 3.

Now, we proceed with the long division:

  • Divide the first term of the dividend, 3x^3, by the first term of the divisor, 2x^2, to get 3/2x.
  • Multiply the entire divisor by 3/2x and subtract this from the dividend.
  • Bring down the next term and repeat these steps until all terms have been used.

After performing these steps, you'll either end up with a remainder of zero, which means the divisor is a factor of the dividend, or with a non-zero remainder, meaning it's not a factor. If we perform this division, we find that there is a remainder, indicating that 2x^2 + 3 is not a factor of 3x^3 - 7x^2 + 5x^2 - 3. Therefore, the correct answer is B) No, it's not a factor.

Lastly, always review the result to ensure it is reasonable and that no errors have occurred during the division process.

User Tim Landscheidt
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