Final answer:
To solve the quadratic equation x² + 0.0211x - 0.0211 = 0, we apply the quadratic formula, yielding two possible solutions, approximately x = 0.0216 or x = -0.0224.
Step-by-step explanation:
The student is asking about solving a quadratic equation of the form ax² + bx + c = 0. We can solve for x using the quadratic formula, which is x = (-b ± √(b² - 4ac)) / (2a). For the given equation x² +0.0211x -0.0211 = 0, we identify a = 1, b = 0.0211, and c = -0.0211. Using the quadratic formula, we can calculate the values for x. We must evaluate both possible signs in the numerator: first the positive sign, yielding one value for x, and then the negative sign, yielding a different value for x. Through this process, we find the two solutions for x could be approximately x = 0.0216 or x = -0.0224.