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An irregular shaped stone was lowered into a graduated cylinder holding a volume of water equal to 20.0mL. The height of the water rose to 32.5mL. If the mass of the stone was , what was its density?

User Silkia
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Final answer:

The density of the stone is its mass divided by the displaced water volume, which is the rise in water level in the graduated cylinder. However, as the mass of the stone is not given, we cannot calculate the exact density.

Step-by-step explanation:

To calculate the density of the stone, we need to divide the mass of the stone by its volume. However, the mass of the stone is missing in the question. If the mass was provided, let's say 'm' grams, the calculation would be straightforward: the volume of the stone is the change in the water level in the graduated cylinder, which is 32.5mL - 20.0mL = 12.5mL. The density formula is Density = Mass / Volume, so the stone's density would be 'm' grams / 12.5 mL (assuming 'm' is known).

For example, if the mass of the stone was 25 grams, the density would be 25 g / 12.5 mL = 2 g/mL. This process of finding density using water displacement is based on Archimedes' principle. Without the actual mass of the stone provided, it's impossible to calculate its precise density.

User Mdameer
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