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A sledder accelerated from rest at 6.84 m/s/s for 2.39 seconds. determine the distance she moved?

User Martim
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1 Answer

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Final answer:

To find the distance the sledder moved after accelerating from rest at 6.84 m/s² for 2.39 seconds, use the kinematic equation s = ut + ½at², which gives a displacement of 19.541 meters hence she moved 19.541 meters.

Step-by-step explanation:

To determine the distance the sledder moved while accelerating from rest at 6.84 m/s² for 2.39 seconds, we can use the kinematic equation for uniformly accelerated motion:

s = ut + ½at²

where:

  • s is the displacement (distance moved)
  • u is the initial velocity, which is 0 m/s since the sledder started from rest
  • a is the acceleration, which is 6.84 m/s²
  • t is the time, which is 2.39 seconds

Plugging in the values into the equation, we have:

s = 0 * 2.39 + ½ * 6.84 * (2.39)²

s = ½ * 6.84 * 5.7121

s = 3.42 * 5.7121

s = 19.541 m

Thus, the sledder moved a distance of 19.541 meters.

User Radu Chiriac
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