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What is the length of the diagonal HJ in the parallelogram below Round to the nearest hundredth

User Zimbabao
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1 Answer

4 votes

Answer:

The length of diagonal HJ is 2.92 units.

Explanation:

Finding the Length of Diagonal HJ:

Identify the coordinates:

Point A is at the origin (0, 0).

Point B is at the width (5, 0).

Point C is at the width and height (5, 3).

Point D is at the height (0, 3).

Point H is the midpoint of diagonal BD and has coordinates (2.5, 1.5).

Visualize the diagonal:

Diagonal HJ connects point H (2.5, 1.5) to point D (0, 3).

Apply the distance formula:

Formula: sqrt((x2 - x1)^2 + (y2 - y1)^2)

Calculate: sqrt((2.5 - 0)^2 + (1.5 - 3)^2)

Simplify and round:

Calculation: sqrt((2.5)^2 + (-1.5)^2) = sqrt(6.25 + 2.25) = sqrt(8.5)

Round to nearest hundredth: sqrt(8.5) ≈ 2.92

Therefore, the length of diagonal HJ is 2.92 units.

What is the length of the diagonal HJ in the parallelogram below Round to the nearest-example-1
User Starkm
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