Question

You pick a card at random without putting the 1st card back you pick a second card at random what is the probability of picking an 8 and then picking a 5

Answer 1

Given:

There are four cards numbered

`5,\text{ }6,\text{ }7,\text{ }8`

Required:

We have to find the probability of picking an 8 and then picking a 5.

Step-by-step explanation:

The possibility of picking an 8 in the first time is 1 out of the four cards.

Therefore the probability of picking an 8 first is

`(1)/(4)`

Now since you did not put the card back so there are three cards now.

So the possibility of picking a 5 in the second time out of the three cards is 1.

Therefore the probability of picking a 5 in the second time is

`(1)/(3)`

Now we multiply both the probabilities to find the required answer.

Hence the probability of picking an 8 and then a 5 is

`(1)/(4)*(1)/(3)=(1)/(12)`

Final answer:

Hence the final answer is

`(1)/(12)`