Final answer:
Without additional information about Sandy's starting position relative to New York City at the beginning of the second day, we cannot determine her exact displacement for that day. However, inferring from the information given, her average velocity on the second day could be calculated as 100 km/hr west if we assume the 300 km on the first day was directly towards the city and the second day involved driving 600 km in 6 hours.
Step-by-step explanation:
To determine Sandy's average velocity on the second day of her trip, we need to know the total displacement and the total time. Displacement is the direct distance between the starting and ending points, and average velocity is given by the equation Vavg = displacement / time. Since the question does not provide the displacement for the second day but instead provides a stopping point 900 km from New York City, we cannot solve for the average velocity without additional information about her starting position relative to New York City at the beginning of the second day. However, if we assume that the 300 km travelled on the first day was directly towards New York City, we could infer that after the first day she was 300 km closer to the city. On the second day, if she stopped 900 km away from New York City, this would mean she covered a distance of 600 km (potentially less if the first day's travel wasn't directly towards the city). Given that she drove for 6 hours, the average velocity for the second day would then be the displacement (600 km) divided by the time (6 hours), which is 100 km/hr. Therefore, the correct statement about her average velocity would be d. 100 km/hr west.