Question

While advertising for Prestige Worldwide, Dale Doback rents a helicopter from Derek Huff to film a commercial when he *all of a sudden* realizes that a velociraptor is flying it, so he kicks the dinosaur off the chopper, who then falls 20,355m to the ground. How fast in m/s was the velociraptor falling when he hit the ground?

Answer 1

To calculate the velociraptor's velocity upon impact after a free fall of 20,355m, the equation for motion under gravity was used, which determined the velociraptor's final impact velocity to be approximately 632.08 m/s.

Step-by-step explanation:

To find out how fast the velociraptor was falling when it hit the ground, we can use the equation of motion under the influence of gravity (ignoring air resistance), which is v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.80 m/s2), and s is the distance fallen. Since the velociraptor started from rest, u equals 0, and the equation simplifies to v = √(2as). Plugging in the values, we get v = √(2 * 9.80 m/s2 * 20,355 m). After calculating, we find that the velociraptor's velocity upon impact was approximately 632.08 m/s.