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How much does a 725 kg elevator weigh?
F = [?]N

User Xklakoux
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Final answer:

The weight of a 725 kg elevator is 7113.25 newtons, calculated using the equation F = mg with g as 9.81 m/s² on Earth.

Step-by-step explanation:

The question asks how much a 725 kg elevator weighs. To find this, we use the equation for weight, which is F = mg, where F is the force due to gravity (or the weight), m is the mass, and g is the acceleration due to gravity. On Earth, g is approximately 9.81 m/s². The calculation would be:

F = 725 kg × 9.81 m/s² = 7113.25 N
Therefore, the weight of the elevator is 7113.25 newtons (N).

User Thomas Kimber
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