Final answer:
The expression that models the volume remaining in the jug after t seconds is 3 - (0.75 * t) - (0.02 * t).
Step-by-step explanation:
The expression that models the volume remaining in the jug, in liters, after t seconds is option C) 3 - (0.75 * t) - (0.02 * t).
To understand why, we need to break down each part of the expression:
- (0.75 * t) represents the volume that was initially filled in the jug and is being poured out at a rate of 20 mL/s.
- (0.02 * t) represents the volume that is being poured out continuously at a rate of 20 mL/s.
By subtracting these two components from the maximum capacity of 3 liters, we get the expression that models the volume remaining after t seconds.