Question

In nursing school, students learn temperature ranges for bath water. Tepid water is approximately 80°F to 93°F, warm water is approximately 94°F to 98°F, and hot water is approximately 110°F to 115°F.

Write a compound inequality representing each of the types of water.

Answer 1

Compound inequalities for bath water temperatures in nursing school are 80°F ≤ temperature ≤ 93°F for tepid water, 94°F ≤ temperature ≤ 98°F for warm water, and 110°F ≤ temperature ≤ 115°F for hot water.

Step-by-step explanation:

The student question relates to setting up compound inequalities for different temperature ranges for bath water as learned in nursing school. The temperature ranges given are tepid water (≈ 80°F to 93°F), warm water (≈ 94°F to 98°F), and hot water (≈ 110°F to 115°F). The corresponding compound inequalities would be:

• Tepid water: 80°F ≤ temperature ≤ 93°F
• Warm water: 94°F ≤ temperature ≤ 98°F
• Hot water: 110°F ≤ temperature ≤ 115°F

Each inequality represents a range in which the temperature of the water can be classified into one of these categories.