Question

1. A car is traveling at an initial velocity of 12 m/s when it experiences a constant acceleration to 62 m/s in a time of 20 s. What is its acceleration?

2. An object moving at a velocity of 32 m/s slows to 8 m/s in 4 seconds. What was its acceleration?

Answer 1

The acceleration in the first scenario is 2.5 m/s² and in the second scenario is -6 m/s².

Step-by-step explanation:

To find the acceleration in the first scenario, we can use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation, we have a = (v-u)/t. In this case, the initial velocity u is 12 m/s, the final velocity v is 62 m/s, and the time t is 20 s. Plugging in these values, we get a = (62-12)/20 = 2.5 m/s².

For the second scenario, we can use the same equation. The initial velocity u is 32 m/s, the final velocity v is 8 m/s, and the time t is 4 s. Plugging in these values, we get a = (8-32)/4 = -6 m/s².