Question

An object of mass 10kg whirled round in a horizontal circle of radius 4m by a revolving string inclined to the vertical. If the uniform speed of the object is 5metres per second. Calculate the tension of the string.​

Answer 1

To calculate the tension in the string, we use the formula for centripetal force (Fc = mv^2/r), with the given mass, speed, and radius. Without the angle of inclination of the string, the tension is assumed to be equal to the centripetal force, which is 62.5 N.

Step-by-step explanation:

The student is asking how to calculate the tension in the string that is whirling an object in a horizontal circle at a uniform speed. Given are the mass of the object (10 kg), the radius of the circle (4 m), and the speed (5 m/s). Applying physics formulas for circular motion, the tension can be calculated through the centripetal force required to maintain the circular motion.

Firstly, we find the centripetal force using the formula Fc = mv2/r, where m is the mass, v is the speed, and r is the radius. Substituting the given values, we have:

Fc = (10 kg) × (5 m/s)2 / (4 m) = 62.5 N.

Since there is no information given about the angle of inclination of the string, we'll assume that the force of tension is equal to the centripetal force required. Therefore, the tension in the string is 62.5 N.