Final answer:
The mass of water displaced by the ice when submerged in water is 30000 grams, calculated using the volume of the ice (which is 30000 cm³) and the density of water, which is 1 gm/cm³.
Step-by-step explanation:
To find the mass of water displaced by the piece of ice when it is kept in water, we should use the known density of ice and the dimensions of the ice to calculate its volume. Then, since ice is less dense than water, it displaces an amount of water equal to its own volume when submerged.
The volume (V) of the ice is calculated by multiplying its length (l), breadth (b), and height (h) together:
V = l × b × h
For the given measurements:
V = 50 cm × 30 cm × 20 cm
V = 30000 cm³
Using the density of water (1 gm/cm³), the mass of water displaced (m) by the ice is simply equal to the volume of the ice since the density of water is used as 1 gm/cm³:
m = V × density of water
m = 30000 cm³ × 1 gm/cm³
m = 30000 grams
Therefore, the mass of water displaced by the ice when it is kept in water is 30000 grams.