206k views
1 vote
What is the smallest power of 10 that would exceed 65,902

1 Answer

3 votes

Final answer:

To determine the smallest power of 10 that would exceed 65,902, we need to find the number of digits in 65,902. Since 65,902 has 5 digits, the power of 10 that would be needed is 10^5 = 100,000.

Step-by-step explanation:

To determine the smallest power of 10 that would exceed 65,902, we need to find the number of digits in 65,902. Since 65,902 has 5 digits, the power of 10 that would be needed is 105 = 100,000.

Another way to determine the power of 10 is to move the decimal point to the right until we have a number between 1 and 10. In this case, we would need to move the decimal point 5 places to the right to get 6.5902. Therefore, the smallest power of 10 that would exceed 65,902 is 105 = 100,000.

User Gunderson
by
7.5k points