Final answer:
The number of elements in the union of sets A and B, which is denoted by n(A ∪ B), is calculated to be 110 using the principle of inclusion and exclusion with the provided values. Thus, the number of elements in the union of sets A and B is 110.
Step-by-step explanation:
To find the number of elements in the union of sets A and B, designated as n(A ∪ B), we use the principle of inclusion and exclusion. This principle can be expressed with the formula:
n(A ∪ B) = n(A) + n(B) - n(A ∩ B),
where:
- n(A) is the number of elements in set A,
- n(B) is the number of elements in set B, and
- n(A ∩ B) is the number of elements in both A and B simultaneously (the intersection of A and B).
Substituting the given values into this formula:
n(A ∪ B) = 80 + 60 - 30,
which simplifies to:
n(A ∪ B) = 110.
Thus, the number of elements in the union of sets A and B is 110.