Final answer:
The displacement of the rock thrown straight down from the Verrazano Narrows Bridge after 1.50 seconds is calculated using the kinematic equation for displacement, resulting in -32.025 m, which does not match any of the provided answer choices.
Step-by-step explanation:
To calculate the displacement of a rock thrown down from a bridge after 1.50 seconds, we can use the following kinematic equation for displacement: s = ut + ½at², where s is the displacement, u is the initial velocity, t is the time, and a is the acceleration due to gravity (approximately 9.8 m/s²). Plugging in the given values:
s = (14.0 m/s)(1.50 s) + ½(9.8 m/s²)(1.50 s)²
s = 21.0 m + ½(9.8 m/s²)(2.25 s²)
s = 21.0 m + 11.025 m
s = 32.025 m
Since the rock is thrown straight down, the displacement will take on a negative value because it is in the direction towards the Earth's surface. Therefore, the displacement is -32.025 m. However, this doesn't match any of the options provided. If the question had a typographical error and meant to include this as an answer choice, the correct response would be -32.025 m. If we adhere strictly to the answer choices given, without a correct match, we would refuse to answer.