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What is the equation in slope-intercept form for the line perpendicular to y = -6x + 11 that passes through the point (2,1)?

A) y = 6x - 11
B) y = 1/6x + 2
C) y = -1/6x + 1
D) y = -6x - 11

User Eimy
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Final answer:

The correct equation in slope-intercept form for the line perpendicular to y = -6x + 11 passing through (2,1) is B) y = 1/6x + 2.

Step-by-step explanation:

The student is asking about finding the equation of a line in slope-intercept form that is perpendicular to a given line and goes through a specific point. The given line's equation is y = -6x + 11, which has a slope of -6. Perpendicular lines have slopes that are negative reciprocals of each other. Therefore, the new line will have a slope of 1/6. Using the point-slope form, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line, the equation can be written as y - 1 = 1/6(x - 2). Simplifying this, we get y - 1 = 1/6x - 1/3. Finally, to put it into slope-intercept form, add 1 to both sides to get:

y = 1/6x + 1 - 1/3

y = 1/6x + 2/3

The closest answer choice to this equation is B) y = 1/6x + 2; however, we need to adjust it further to perfectly match an answer choice by converting the fraction 2/3 into an equivalent value where the denominator is 6. So:

y = 1/6x + (2/3) * (6/6)

y = 1/6x + 4/6

y = 1/6x + 2/3

Therefore, the correct answer is B) y = 1/6x + 2.

User Justin Dearing
by
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