30.6k views
0 votes
What is the cutting speed in surface feet per minute of a 20-in bandsaw if the wheel turns at 800 RPM?

A) 2090 ft/min
B) 2300 ft/min
C) 1830 ft/min
D) 1950 ft/min

User Phanto
by
8.4k points

1 Answer

4 votes

Final answer:

The cutting speed of the 20-inch bandsaw, rotating at 800 RPM, is approximately 2090 ft/min. Hence, option A) 2090 ft/min is the correct choice. This metric is crucial for machining efficiency, indicating the saw's performance in various applications like woodworking and metalworking.

Step-by-step explanation:

The cutting speed of a 20-inch bandsaw, revolving at 800 RPM, is determined by multiplying the wheel's diameter by the rotational speed and the constant \(\pi\). The calculated cutting speed is approximately 2090 feet per minute, making options A) 2090 ft/min the accurate choice. This metric, known as surface feet per minute (sfpm), is crucial in machining processes, influencing the efficiency and precision of cutting operations. The bandsaw's capability to deliver a cutting speed of 2090 ft/min is indicative of its performance, ensuring effective material removal and accurate cutting, enhancing its utility in various woodworking and metalworking applications.

User Kronos
by
7.7k points