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What is the speed of the ball after 1 second when thrown upward with a speed of 60 m/s?

A) 54 m/s
B) 50 m/s
C) 46 m/s
D) 40 m/s

1 Answer

4 votes

Final answer:

The speed of the ball after 1 second when thrown upward with a speed of 60 m/s is 50 m/s.

Step-by-step explanation:

To find the speed of the ball after 1 second when thrown upward with a speed of 60 m/s, we need to consider the effects of gravity. The velocity of the ball at any given time can be found using the equation:

final velocity = initial velocity + (acceleration * time)

Since the ball is thrown upward, the acceleration due to gravity will have a negative value (-9.8 m/s^2). Plugging in the values, we have:

final velocity = 60 m/s + (-9.8 m/s^2 * 1 s)

Calculating this, we find that the final velocity of the ball after 1 second is 50.2 m/s. Therefore, the correct answer is 50 m/s (Option B).

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